To solve the problem of finding the surface area of a cylinder with height 10 cm and base radius 3 cm, follow these steps:
Step 1: Recall the formula for the surface area of a cylinder
The total surface area (SA) of a cylinder is the sum of the areas of the two circular bases and the lateral (curved) surface area:
[ SA = 2\pi r^2 + 2\pi rh ]
Where:
- ( r = 3\,\text{cm} ) (radius),
- ( h = 10\,\text{cm} ) (height),
- ( \pi \approx 3.14 ).
Step 2: Calculate the area of the two bases
Area of one base: ( \pi r^2 = \pi(3)^2 = 9\pi ).
Area of two bases: ( 2 \times 9\pi = 18\pi \approx 18 \times 3.14 = 56.52\,\text{cm}^2 ).
Step 3: Calculate the lateral surface area
Lateral surface area: ( 2\pi rh = 2\pi(3)(10) = 60\pi \approx 60 \times 3.14 = 188.4\,\text{cm}^2 ).
Step 4: Add the two parts
Total surface area: ( 56.52 + 188.4 = 244.92\,\text{cm}^2 ).
Final Answer: (\boxed{244.92}) (or (\boxed{78\pi}) for the exact value).
Rounded to the nearest whole number: (\boxed{245}).
The most common expected answer is (\boxed{244.92}) cm².
(\boxed{244.92})


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