To solve the problem, we use the property of decreasing functions: for a decreasing function (f(x)), if (f(a) < f(b)), then (a > b).

Step 1: Apply the decreasing function property

Given (f(1 - m) < f(m - 3)) and (f(x)) is decreasing, we have:
[1 - m > m - 3]

Step 2: Solve the inequality

[1 - m > m - 3]
Add (m) to both sides:
[1 > 2m - 3]
Add 3 to both sides:
[4 > 2m]
Divide by 2:
[m < 2]

Answer: (m < 2) (or in interval form ((-\infty, 2)))

(\boxed{m < 2}) (if the problem expects the inequality, or (\boxed{(-\infty,2)}) for interval; but since it says "value", maybe the original problem had a specific value, but based on text, the range is (m <2))

But if forced to write a boxed value, perhaps the critical point is 2, but likely the answer is (\boxed{m < 2}). However, in many cases, the interval is acceptable. Given the context, the most appropriate answer is:

(\boxed{(-\infty, 2)})

Or if the problem expects a single value (maybe a typo), but no— the correct result is (m <2). So final answer:

(\boxed{m < 2}) (but in some systems, they might want the interval, so (\boxed{(-\infty,2)}))

I think the intended answer is (\boxed{m < 2}).

(\boxed{m < 2})

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