To solve the problem, we first analyze the pattern of the sequence:
Step 1: Identify the sequence pattern
The sequence starts at 1, and skips multiples of 5. For every 5 natural numbers, we keep 4 (since we skip the 5th multiple).
Example: 1-5 → keep 1,2,3,4 (4 numbers); 6-10 → keep 6,7,8,9 (4 numbers); etc.
Step 2: Relate the sequence position to natural numbers
Each group of 4 numbers in our sequence corresponds to 5 natural numbers (4 kept + 1 skipped).
For the k-th group of 4 numbers:
- The last number in the k-th group is (5k - 1) (since group k covers (5(k-1)+1) to (5k), and we skip (5k)).
Step 3: Calculate the 2012th number
2012 numbers = (2012 ÷ 4 = 503) full groups.
The last number of the 503rd group is:
(5×503 - 1 = 2515 - 1 = 2514).
Answer: 2514.


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