It seems the problem statement is missing. Assuming a common problem like Two Sum (find two numbers in an array that add up to a target), here's a simple Python solution:

Problem Assumption: Two Sum

Given an array of integers nums and an integer target, return indices of the two numbers such that they add up to target.

Approach

Use a hash map (dictionary) to store the numbers we've seen so far and their indices. For each number:

1. Calculate the complement (target minus current number).
2. If the complement exists in the hash map, return its index and the current index.
3. Otherwise, add the current number and its index to the hash map.

This approach runs in O(n) time (each lookup in the hash map is O(1)).

Solution Code

def two_sum(nums, target):
    seen = {}
    for idx, num in enumerate(nums):
        complement = target - num
        if complement in seen:
            return [seen[complement], idx]
        seen[num] = idx
    return []  # No solution (problem usually guarantees one)

Explanation

• Hash Map: Tracks numbers we've processed to avoid rechecking.
• Complement Check: For each number, we check if the required complement (to reach the target) is already in the map.
• Efficiency: Single pass through the array, so it's optimal for large inputs.

If the actual problem differs, please provide the full problem statement for a tailored solution!
Let me know if you need help with another problem.

作者声明:本文包含人工智能生成内容。