To solve this problem, we need to analyze the sequence formed by multiplying the digits of the previous term until we reach a single-digit number (since a single-digit number's product of digits is itself, it remains constant thereafter).
Step 1: Assume the initial term (common in such problems)
Let’s take the initial term as 679 (a typical starting number for this problem):
- Term 1: 679
- Term 2: 6×7×9 = 378
- Term 3: 3×7×8 = 168
- Term 4: 1×6×8 = 48
- Term 5: 4×8 = 32
- Term 6: 3×2 = 6
- Term 7 onwards: 6 (since 6×1=6, it stays constant)
Step 2: Determine the 2016th term
After term 6, all subsequent terms are 6. Since 2016 > 6, the 2016th term is 6.
Answer: 6


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