To solve the problem of finding the number of arrangements of the word "SUCCESS" where the two 'C's are not next to each other, follow these steps:

Step 1: Calculate total arrangements of "SUCCESS"

The word "SUCCESS" has 7 letters: S(3), U(1), C(2), E(1).
Total arrangements = $\frac{7!}{3! \times 2!}$ (accounting for repeated S and C).
$\frac{5040}{6 \times 2} = 420$.

Step 2: Calculate arrangements where the two 'C's are next to each other

Treat the two 'C's as a single block [CC]. Now we have 6 units: [CC], S(3), U(1), E(1).
Arrangements = $\frac{6!}{3!}$ (only S is repeated 3 times).
$\frac{720}{6} = 120$.

Step 3: Subtract the unwanted arrangements

Number of valid arrangements = Total arrangements - arrangements with Cs together.
$420 - 120 = 300$.

Answer: $\boxed{300}$

作者声明:本文包含人工智能生成内容。