To find the area of the triangle with vertices at ((0,0)), ((1,2)), and ((3,1)), we use the shoelace formula for three points ((x_1,y_1)), ((x_2,y_2)), ((x_3,y_3)):
Step 1: Apply the shoelace formula
The formula is:
[ \text{Area} = \frac{1}{2} \left| x_1(y_2 - y_3) + x_2(y_3 - y_1) + x_3(y_1 - y_2) \right| ]
Substitute the points ((0,0)), ((1,2)), ((3,1)):
[ \text{Area} = \frac{1}{2} \left| 0(2-1) + 1(1-0) + 3(0-2) \right| ]
Step 2: Calculate the expression inside the absolute value
[ 0(1) + 1(1) + 3(-2) = 0 + 1 - 6 = -5 ]
Step 3: Take absolute value and multiply by (\frac{1}{2})
[ \text{Area} = \frac{1}{2} \times |-5| = \frac{5}{2} = 2.5 ]
Answer: (\boxed{\dfrac{5}{2}}) (or (\boxed{2.5}) if decimal is allowed)
But since exact fractions are preferred in math problems, the final answer is:
(\boxed{5/2}) (or (\boxed{2.5}) depending on format, but (\boxed{5/2}) is exact).
(\boxed{5/2})

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