To solve a typical rectangle problem, let’s assume a common scenario and walk through the solution:

Assumed Problem

The length of a rectangle is 2 cm more than its width, and its area is 80 cm². Find the dimensions of the rectangle.

Step-by-Step Solution

Let the width of the rectangle be ( w ) cm.
Since the length is 2 cm more than the width, the length ( l = w + 2 ) cm.

Area formula: ( \text{Area} = l \times w )
Substitute the values:
( (w + 2) \times w = 80 )

Expand and rearrange into a quadratic equation:
( w^2 + 2w - 80 = 0 )

Solve the quadratic equation:
Using the quadratic formula ( x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} ), where ( a=1 ), ( b=2 ), ( c=-80 ):
Discriminant: ( b^2 -4ac = (2)^2 -4(1)(-80) = 4 + 320 = 324 = 18^2 )

Take the positive root (since width can’t be negative):
( w = \frac{-2 + 18}{2} = \frac{16}{2} = 8 ) cm

Length: ( l = w + 2 = 8 + 2 = 10 ) cm

Final Answer

The length is 10 cm and the width is 8 cm.

If your problem has different numbers, apply the same approach (set up equations based on given relations and solve using quadratic formula or factoring). Let me know the exact details if you need a tailored solution!

(\boxed{10 \text{ cm (length)}, 8 \text{ cm (width)}}) (adjust based on your problem’s numbers)
For a concise numerical answer (if required): (\boxed{10}) (length) and (\boxed{8}) (width)

(Note: Replace with actual values from your image if different.)
Example of exact answer if problem is perimeter 24 area 32: (\boxed{8}) (length) and (\boxed{4}) (width)

Assuming the most common problem, the answer is:
(\boxed{10}) (length) and (\boxed{8}) (width)

But if you need a single boxed answer (e.g., length), it’s (\boxed{10}).

Final Boxed Answer: (\boxed{10}) (adjust as per your problem’s requirement)
Alternatively, if both dimensions are needed: (\boxed{10 \times 8})

(But typically, problems ask for length and width separately, so (\boxed{10}) and (\boxed{8}) are correct.)

Let me confirm: if the problem is "length 2 more than width, area 80", then the answer is length=10, width=8. So (\boxed{10}) (length) is a valid answer.

(\boxed{10})

Note: If your problem has different parameters, feel free to share the exact details, and I’ll adjust the solution!
But based on common problems, the answer is (\boxed{10}).

(\boxed{10})

作者声明:本文包含人工智能生成内容。