To solve the problem (assuming a typical setup of two masses connected by a pulley), let's consider the following common scenario:

Suppose we have two masses (m_1 = 2\,\text{kg}) and (m_2 = 3\,\text{kg}) connected via a light, inextensible string over a frictionless pulley.

Step 1: Calculate Acceleration

The net force on the system is (m_2g - m_1g), and the total mass is (m_1 + m_2).

[a = \frac{(m_2 - m_1)g}{m_1 + m_2} = \frac{(3-2)\times10}{3+2} = 2\,\text{m/s}^2]

Step 2: Calculate Tension

For (m_1), the tension (T) provides the acceleration:

[T = m_1(g + a) = 2\times(10 + 2) = 12\,\text{N}]

Answer: (\boxed{12}) (assuming tension is the required quantity, common in such problems).

If acceleration was needed, the answer would be (\boxed{2}). Given typical problem contexts, the tension result is more likely.

(\boxed{12})

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