To address a common programming problem (since the image link is inaccessible), let's solve the Maximum Subarray Sum problem using Kadane's Algorithm. This is a classic problem where we find the contiguous subarray with the largest sum.
Problem Statement (Assumed)
Given an integer array, find the contiguous subarray (containing at least one element) which has the largest sum and return its sum.
Approach (Kadane's Algorithm)
- Initialization: Start with
current_max(sum of the current subarray) andglobal_max(maximum sum found so far) set to the first element of the array. - Iterate: For each subsequent element:
- Update
current_maxto be the maximum of the element itself or the sum ofcurrent_maxplus the element (this decides whether to start a new subarray or continue the existing one). - Update
global_maxifcurrent_maxexceeds it.
- Update
- Result:
global_maxwill hold the largest sum of any contiguous subarray.
C++ Code
#include <iostream>
#include <vector>
#include <algorithm> // For std::max
using namespace std;
int maxSubArray(vector<int>& nums) {
if (nums.empty()) return 0;
int current_max = nums[0];
int global_max = nums[0];
for (size_t i = 1; i < nums.size(); ++i) {
current_max = max(nums[i], current_max + nums[i]);
global_max = max(global_max, current_max);
}
return global_max;
}
int main() {
// Example input
vector<int> nums = {-2, 1, -3, 4, -1, 2, 1, -5, 4};
cout << "Maximum Subarray Sum: " << maxSubArray(nums) << endl;
// Output: 6 (subarray [4, -1, 2, 1])
return 0;
}
Explanation
- Initialization:
current_maxandglobal_maxstart at-2(first element of the example input). - Iteration:
- For
1,current_max = max(1, -2+1)=1,global_max=1. - For
-3,current_max = max(-3,1-3)=-2,global_max remains 1. - For
4,current_max = max(4, -2+4)=4,global_max=4. - And so on until the end of the array.
- For
- Result: The largest sum is
6(from the subarray[4, -1, 2, 1]).
If the original problem was different, feel free to provide the problem statement, and I'll adjust the solution accordingly!


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