To solve the problem, we assume the context of a common additive function problem:

Key Observations:

If (f(x)) is an additive function satisfying (f(x+y) = f(x) + f(y)) for all (x,y), and (f(1) = 1), then for any integer (n):
(f(n) = f(1+1+\dots+1) = n \cdot f(1) = n).

Application to the Problem:

For (n = 2023), (f(2023) = 2023).

Answer: (\boxed{2023})

作者声明:本文包含人工智能生成内容。