To solve this problem, we need to account for the net gain each day (daytime climb minus nighttime slip) except the final day, when the person reaches the top and does not slip down.
Key Observations:
- Daily climb: 5 meters (daytime).
- Nightly slip: 3 meters (nighttime).
- Net gain per full cycle (day + night): (5 - 3 = 2) meters.
- Final day: Once the person climbs 5 meters to reach or exceed 100 meters, they stop (no slip).
Calculation:
Let (k) be the total number of days needed to reach the top.
On the final day ((k)-th day), the person does not slip, so they only slip (k-1) times.
Total height formula:
[5k - 3(k-1) \geq 100]
Simplify:
[5k -3k +3 \geq100]
[2k +3 \geq100]
[2k \geq97]
[k \geq48.5]
Since (k) must be an integer, the minimal (k) is 49.
Answer: 49 days.
(\boxed{49})
作者声明:本文包含人工智能生成内容。